Swapping two numbers without using a third variable

By Sidharth Patnaik -
This is a program using which you can swap two numbers without using a third variable.
This program is crafted using Java Language.

import java.util.Scanner;
class swap
{
     public static void main (String []args)
     {
            Scanner s= new Scanner(System.in);
            System.out.print("Enter The Value Of A: ");
            int a=s.nextInt();
            System.out.print("Enter The Value Of B: ");
            int b=s.nextInt();
            a=a+b;
            b=a-b;
            a=a-b;
            System.out.println("Swapped, a: "+a+", b: "+b);
      }
}

Description:
This program swaps the two number without using a third value. Let say the value of a is 10 and b is 5.
First Calculation: a=a+b, So a=10+5=15.
Second Calculation: b=a-b, So b=15-5=10.
Third Calculation: a=a-b, So a=15-10=5.
Now the values of both a and b have successfully changed. Instead of add and sub, you can alternatively use mul and div.
The Complexity is of order 1, O(1).

Comments

Post a Comment

Popular posts from this blog

Non Restoring Division Algorithm Implementation in C

By Sidharth Patnaik -
Image
This  is a Dynamic program for the implementation of the NON RESTORING Division Algorithm in C Language. Non Restoring Division uses Left Shift Operations, Twos' Compliment and Binary Addition. Screenshots[Demo] The Code #include<stdio.h> #include<malloc.h> int *a,*q,*m,*mc,*c,n,d; int powr(int x,int y) { int s=1,i; for(i=0;i<y;i++) s=s*x; return s; } void print(int arr[],int n) { int i; for(i=0;i<n;i++) printf("%d ",arr[i]); } void bin(int n, int arr[]){ int r, i = 0; do{ r = n % 2; n /= 2; arr[i] = r; i++; }while(n > 0); } void set(int array[], int x){ int i,tmp[20]={0}; for(i = x -1; i >=0; i--) tmp[x-1-i]=array[i]; for(i=0;i<x;i++) array[i]=tmp[i]; } int len(int x) { int i=0; while(powr(2,i)<=x) i++; return ++i; } void addBinary(int a1[], int a2[]) { int bi[2]={0},ca[20]={0}; int t=len(n),tmp=0; int *su=(int*)malloc(sizeof(int)*len(n)); while(t...
Read more

Hackerrank String Reduction Solution

By Sidharth Patnaik -
Image
This is the solution to the program, solved in python. The Question can be found in the Algorithm domain of Hackerrank. Problem Statement: Given a string consisting of letters, a, b and c, we can perform the following operation: Take any two adjacent distinct characters and replace them with the third character. For example, if 'a' and 'c' are adjacent, they can replaced by 'b'. Find the smallest string which we can obtain by applying this operation repeatedly? Screenshots[Demo] The Code: def cnt(x): m={} m['a']=0;m['b']=0;m['c']=0 for c in x: if c not in m: m[c]=1 else: m[c]+=1 return m def red(x): xm=cnt(x) print x,xm if((xm['a']==0 and xm['b']==0 ) or (xm['a']==0 and xm['c']==0 ) or (xm['b']==0 and xm['c']==0)): return len(x); if((xm['a']%2==0 and xm['b']%2==0 and xm['c']%2==0) or (...
Read more

Bit Stuffing Code Implementation in Java

By -
Image
This is an implementation of the Bit Stuffing popularly used in data communication, also known as one of the concepts of Framing data bits. To know more please  click here. Sample Output: This is a sample output with data binary data entered as 11001111110. Program Code: import java.util.*; public class BitStuffing { public static void main(String[] args) { System.out.print("Enter the Binary message: "); Scanner sn=new Scanner(System.in); String data = sn.nextLine(); String res = new String(); String out=new String(); int counter = 0; for(int i=0;i<data.length();i++) { if (data.charAt(i)!='1' && data.charAt(i)!='0') { System.out.println("Enter only Binary values!!!"); return; } ...
Read more