Number of squares present between two numbers

The following program prints the number of squares present between two numbers.The program is implemented using C++ language.
Ex:
Let the two numbers be 3 and 9.
There are two squares between them i.e. 4 and 9.So the output will be 2.

#include<iostream>
#include<math.h>
using namespace std;

int main()
{
   int x,y;
   cout<<"Enter two elements : "<<endl;
   cin>>x>>y;
   x=sqrt(x-1);
   y=sqrt(y);
   cout<<"\nThe number of squares present : "<<(y-x);
   return 0;
}

Description : 

In the above program let the two elements be A and B. x is the square root of A and y is the square root of B. The squares of x and y lies in between A and B. Therefore square of elements present between x and y are also present in the range of A and b.

Ex:

5 and 20 are two elements for the program.
x=sqrt(5-1)=2 and y=sqrt(20)=4
According to program the count will be 2.9 and 16 are only two square elements present between 5 and 20.

Output:

Case 1:

Enter two elements :
3 9
The number of squares present : 2

Case 2:

Enter two elements :

15 24

The number of squares present : 1

Case 3:

Enter two elements :
25 49
The number of squares present : 3