Hackerrank Fibonacci Modified Recursive Solution

By Sidharth Patnaik -
This is the solution for the Fibonacci Modified Problem found under the dynamic programming section at hackerrank. You need to find the (n+k)th term of the generated series, where nth and (n+1)th term will be supplied as input.

The nth and (n+1)th terms, the (n+2)th can be computed by the following relation :
Tn+2 = (Tn+1)2 + Tn

So, if the first two terms of the series are 0 and 1 and k is 5 then
the third term = 12 + 0 = 1
fourth term = 12 + 1 = 2
fifth term = 22 + 1 = 5

Screenshots[Demo]



The Code

def fibo(a,b,n):
    if(n==0):
        return b;
    else:
        return fibo(b,b**2+a,n-1)
x=raw_input()
x=x.split()
print fibo(int(x[0]),int(x[1]),int(x[2])-2)

Found Bugs, feel free to report them !

Comments

Post a Comment

Popular posts from this blog

Non Restoring Division Algorithm Implementation in C

By Sidharth Patnaik -
Image
This  is a Dynamic program for the implementation of the NON RESTORING Division Algorithm in C Language. Non Restoring Division uses Left Shift Operations, Twos' Compliment and Binary Addition. Screenshots[Demo] The Code #include<stdio.h> #include<malloc.h> int *a,*q,*m,*mc,*c,n,d; int powr(int x,int y) { int s=1,i; for(i=0;i<y;i++) s=s*x; return s; } void print(int arr[],int n) { int i; for(i=0;i<n;i++) printf("%d ",arr[i]); } void bin(int n, int arr[]){ int r, i = 0; do{ r = n % 2; n /= 2; arr[i] = r; i++; }while(n > 0); } void set(int array[], int x){ int i,tmp[20]={0}; for(i = x -1; i >=0; i--) tmp[x-1-i]=array[i]; for(i=0;i<x;i++) array[i]=tmp[i]; } int len(int x) { int i=0; while(powr(2,i)<=x) i++; return ++i; } void addBinary(int a1[], int a2[]) { int bi[2]={0},ca[20]={0}; int t=len(n),tmp=0; int *su=(int*)malloc(sizeof(int)*len(n)); while(t...
Read more

Bit Stuffing Code Implementation in Java

By -
Image
This is an implementation of the Bit Stuffing popularly used in data communication, also known as one of the concepts of Framing data bits. To know more please  click here. Sample Output: This is a sample output with data binary data entered as 11001111110. Program Code: import java.util.*; public class BitStuffing { public static void main(String[] args) { System.out.print("Enter the Binary message: "); Scanner sn=new Scanner(System.in); String data = sn.nextLine(); String res = new String(); String out=new String(); int counter = 0; for(int i=0;i<data.length();i++) { if (data.charAt(i)!='1' && data.charAt(i)!='0') { System.out.println("Enter only Binary values!!!"); return; } ...
Read more

Hackerrank Modified Kaprekar Numbers Solution

By Sidharth Patnaik -
Image
This is the solution to the Modified Kaprekar Numbers found in the implementation section of the algorithm domain in Hackerrank. A modified Kaprekar number is a positive whole number n with d digits, such that when we split its square into two pieces - a right hand piece r with d digits and a left hand piece l that contains the remaining d or d−1 digits, the sum of the pieces is equal to the original number (i.e. l + r = n) . Screenshot The Code def sendKap(x,s): y=x*x y=str(y) s1=y[:len(y)/2:] s2=y[len(y)/2::] s3=int(s1)+int(s2) if(s3==x): s.append(str(x)) st=input() en=input() s=[] for i in range(st,en+1): if(i>9): sendKap(i,s) elif(i==1): s.append(str(i)) elif(i==9): s.append(str(i)) if(len(s)==0): print 'INVALID RANGE' else: print ' '.join(s) Got any problems feel free to comment them here !
Read more